# Doubt

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## Doubt

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## Re: Doubt

 In reply to this post by Halflife If g has jumps at x1,x2,x3 g-1(X) will have jumps at g-1(x1), g-1(x2), g-1(x3) So if g is left continuous, g-(1) will be right continuous and vice versa. An easy way to see is that the graph of inverse of a function is just the axes flipped(interchanged) So if you turn your notebook 90 degree, look at the y axis as new x, and x axiis as new y, what you'll see is the graph of g-1(x), which will be right continuous if g is left continuous.
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## Re: Doubt

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