Doubt

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Doubt

Halflife
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Re: Doubt

Halflife
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Re: Doubt

alibaba
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Is the answer 1/2?

if you open each term using a^2- b^2= (a-b)(a+b)
what remains is
1/2* (n+1)/ n

Applying the limit it becomes 1/2
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Re: Doubt

Halflife
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Re: Doubt

Seecha
This post was updated on .
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MAC
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Re: Doubt

MAC
I got the same result as Alibaba...1/2
Just write the generic term and everything cancels out to give you

1/2*(n+1)/n